## Practice Problems: Measures of Central Tendency - Answer

Bailey has been playing golf on the weekends for the past three years. Recently, she started keeping track of her recorded scores. Her scores for June and July at her favorite 9-hole (par 36) golf course are provided below.

 Data Array 45 56 49 49 42 45 56 42 41 42 36 41 34 41 38 41 41 41 40 40 42 40 41 39 39 39 38 38 40 38 39 36 36 36 41 34

## Mean

 Mean = X / N = 738 / 18 = 41

## Median

 34 36 36 38 38 39 39 40 40 41 41 41 41 42 42 45 49 56

The median is 40.5 . The two middle scores are 40 and 41. By adding these two numbers together and dividing by 2, I find the median = 40.5. Half of the scores fall above this number and half fall below.

## Mode

Mode is equal to 41. It occurs 4 times; all other scores occur only 3 times or less

## What does this information tell you about Bailey's golf game?

Bailey's mean score for the months of June and July is 41 (only 5 above par). Over half of Bailey's games had a score above 40.5 and half had a score below 40.5. Her most common golf score was a 41.

## Is this data skewed?

No. The data is not skewed. The mean and median are almost identical, only a half-stroke difference.

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