## Practice Problems: Measures of Variability - Answer

Bailey has been playing golf on the weekends for the past three years. Recently, she started keeping track of her recorded scores. Her scores for June and July at her favorite 9-hole (par 36) golf course are provided below.

 X X2 56 3136 49 2401 45 2025 42 1764 42 1764 41 1681 41 1681 41 1681 41 1681 40 1600 40 1600 39 1521 39 1521 38 1444 38 1444 36 1296 36 1296 34 1156 738 30692

## Standard Deviation

 S = 18 (30692) - 7382 18 (18-1)

S = 5.0526638

## Variance

The variance is 25.529412. The standard deviation is 5.0526638. The variance is the square of the standard deviation. 5.0526638 squared is equal to 25.529412.

S2 = 25.529412

## Range

The range is 22. The high score is 56; the low score is 34. 56 - 34 = 22.

Range = 22

## What does this information tell you about the variability in Bailey's golf game?

Bailey's golf game appears to be fairly consistent (at least by my standards in relation to my golf game). She is somewhat consistently within 5 strokes of her mean performance.

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